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Jan 02, 2020 · However, the tension in both sections of rope is equal, even if both ends of the rope are being pulled by forces of different magnitudes. For a system of two masses hanging from a vertical pulley, tension equals 2g(m 1)(m 2)/(m 2 +m 1), where "g" is the acceleration of gravity, "m 1" is the mass of object 1, and "m 2" is the mass of object 2.

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We apply Newton's second law: F = m*a Formula ( 1) F : Resulting force acting on the object (N) m : mass of the object (kg) a : total acceleration of the object (m/s²) We replace F= R= 65.59 N and m= 16 kg in the formula (1) to calculate the acceleration of the object : F = m*a. a= F/m. a= 65.59/16.

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16. Acting as medium with intent to deceive. assault means the act of intentionally applying or attempting to apply force to the person of another, directly or indirectly, or threatening by any act or gesture to apply such force to the person of another, if the person making the threat has, or causes...

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15. A 3.0 N force to the right acts on a 0.5 kg object at rest during a time interval of 1.5 seconds. a. What is the velocity of the object at the end of this interval? b. At the end of this interval, a new constant force of 2.0 N to the left is applied for 1.5 sec. What is the velocity at the end of the 1.5 sec? 16.

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if the two forces are acting in same direction, then the net force is equal to the sum of the forces. So, the net force = F1+F2 =10 N+F2. from the Newton's second law of motion, Fnet =m*a. 10 N+F2 = 6.00 kg * 2.00 m/s^2. 10 N +F2 = 12 N. F2 =12 N-10 N =2 N. in the second case that is forces are in opposite, the second force is 22 N.

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If acceleration is directly proportional to the applied net force, then by whatever factor acceleration changes, force changes by the same factor. To see this we will need to consider an object with constant mass. Let's consider an object with a mass of 5 kg. Suppose this object has an acceleration of 3 m/s 2. Let's call this a 1. So: